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28b^2-4b-24=0
a = 28; b = -4; c = -24;
Δ = b2-4ac
Δ = -42-4·28·(-24)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-52}{2*28}=\frac{-48}{56} =-6/7 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+52}{2*28}=\frac{56}{56} =1 $
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